Question:

Match List - I with List - II.
Choose the correct answer from the options given below:

Show Hint

Start with Expression C because it is the simplest:
Half of 1% is $0.5\% = 0.005$. Subtracting 0.005 results in 0.
Matching C to II instantly eliminates two options, leaving only options (A) and (D).
Evaluating Expression A next completes the matching.
Updated On: Jul 18, 2026
  • A-IV, B-II, C-III, D-I
  • A-I, B-III, C-IV, D-II
  • A-II, B-I, C-IV, D-III
  • A-IV, B-III, C-II, D-I
Show Solution
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Question:
This question requires performing arithmetic operations based on percentages and fractions for each expression in List-I and matching the resulting values with the numbers in List-II.

Step 2: Detailed Explanation:


Evaluate Expression A: \[ (75\% \text{ of } 300) + (20\% \text{ of } 210) \] \[ = \left(\frac{75}{100} \times 300\right) + \left(\frac{20}{100} \times 210\right) \] \[ = (75 \times 3) + (2 \times 21) \] \[ = 225 + 42 = 267 \] This value matches List-II (IV).

Evaluate Expression B: \[ (8.5\% \text{ of } 25) - (9\% \text{ of } 70) \] \[ = \left(\frac{8.5}{100} \times 25\right) - \left(\frac{9}{100} \times 70\right) \] \[ = \frac{212.5}{100} - \frac{630}{100} \] \[ = 2.125 - 6.3 = -4.175 \] This value matches List-II (III).

Evaluate Expression C: "Half of 1 percent" can be expressed as: \[ \text{Half of } 1\% = 0.5\% = \frac{0.5}{100} = 0.005 \] Now, calculate the expression: \[ (\text{Half of } 1\text{ percent}) - 0.005 = 0.005 - 0.005 = 0 \] This value matches List-II (II).

Evaluate Expression D: \[ 45\% \text{ of } 25\% \text{ of } \frac{4}{5}\text{th of } 850 \] First, find $\frac{4}{5}\text{th}$ of 850: \[ \frac{4}{5} \times 850 = 4 \times 170 = 680 \] Next, calculate 25% of 680: \[ 25\% \text{ of } 680 = \frac{1}{4} \times 680 = 170 \] Finally, calculate 45% of 170: \[ \frac{45}{100} \times 170 = 4.5 \times 17 = 76.5 \] This value matches List-II (I).

Step 3: Final Answer:

The matching pairs are:
A $\rightarrow$ IV
B $\rightarrow$ III
C $\rightarrow$ II
D $\rightarrow$ I
This combination corresponds to option (D).
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