Question

Match List-I with List-II. 

List-I	Complex / Ion
A	[CoCl₂(NH₃)₄]
B	[Co(NH₃)₆]Cl₃
C	[NiCl₄]²⁻
D	[Fe(CO)₅]

 

List-II	Shape / Geometry
I	Octahedral
II	Trigonal bipyramidal
III	Square planar
IV	Tetrahedral

• A. A-I, B-I, C-IV, D-II
• B. A-IV, B-I, C-III, D-II
• C. A-I, B-IV, C-II, D-III
• D. A-III, B-IV, C-I, D-II

Hint:

Coordination number \(6\) usually gives octahedral geometry, while \([Fe(CO)_5]\) is trigonal bipyramidal.

Answer 1

The Correct Option is A

Step 1: Geometry of \( [CoCl_2(NH_3)_4] \).
This complex has coordination number: \[ 6 \] Coordination number \(6\) generally gives: \[ \text{Octahedral geometry} \] So: \[ A-I \]

Step 2: Geometry of \( [Co(NH_3)_6]Cl_3 \).
The complex ion is: \[ [Co(NH_3)_6]^{3+} \] It has six ammonia ligands. Thus, coordination number is: \[ 6 \] So geometry is: \[ \text{Octahedral} \] Therefore: \[ B-I \]

Step 3: Geometry of \( [NiCl_4]^{2-} \).
Nickel with chloride ligands usually forms a tetrahedral complex in: \[ [NiCl_4]^{2-} \] So: \[ C-IV \]

Step 4: Geometry of \( [Fe(CO)_5] \).
Iron pentacarbonyl has coordination number: \[ 5 \] The geometry of: \[ [Fe(CO)_5] \] is: \[ \text{Trigonal bipyramidal} \] So: \[ D-II \] Therefore, the correct matching is: \[ A-I,\quad B-I,\quad C-IV,\quad D-II \]