Question:

Match List - I with List - II: A. $\mu_{i}$, B. $\overline{V}_{i}$, C. $\overline{S}_{i}$, D. $\mu_{i}^{\circ}$. Relations: I. $(\frac{\partial\mu i}{\partial p})_{T,n_{i}}$, II. $(\frac{\partial G}{\partial ni})_{T,P,n_{j}}$, III. $-(\frac{\partial\mu i}{\partial T})_{P,n_{i}}$, IV. $\mu_{i}-RT~ln~p_{i}$.}

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Chemical potential is just "Gibbs per mole."
Updated On: May 15, 2026
  • A-II, B-I, C-III, D-IV
  • A-I, В-II, C-IV, D-III
  • A-III, B-I, C-II, D-IV
  • А-ІІ, В-III, C-IV, D-I
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The Correct Option is A

Solution and Explanation


Step 1: Concept
This question deals with partial molar quantities and chemical potential ($\mu$).

Step 2: Meaning
$\mu_{i}$ is the partial molar Gibbs free energy.

Step 3: Analysis
A. Chemical potential $\mu_{i}$ is defined as $(\partial G/\partial n_{i})$ (II). B. Partial molar volume $\overline{V}_{i}$ is the derivative of chemical potential with respect to pressure (I). C. Partial molar entropy $\overline{S}_{i}$ is the negative derivative of chemical potential with respect to temperature (III). D. Standard chemical potential $\mu_{i}^{\circ}$ is related to pressure via the activity relation (IV).

Step 4: Conclusion
The correct matches correspond to Option (A). Final Answer: (A)
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