Question

Match List I (Tithi) with List II (Nandādi Group Classification):

List I		List II
A.	Pratipadā (1st)	I.	Bhadrā
B.	Caturthī (4th)	II.	Nandā
C.	Saptamī (7th)	III.	Riktā
D.	Trayōdaśī (13th)	IV.	Jayā

• A. A-III, B-II, C-IV, D-I
• B. A-II, B-III, C-I, D-IV
• C. A-I, B-II, C-IV, D-III
• D. A-III, B-I, C-II, D-IV

Hint:

Remember the count of five: 1-N, 2-B, 3-J, 4-R, 5-P. For any tithi, subtract multiples of 5 and check the remainder! Remainder 1 = Nanda, 2 = Bhadra, 3 = Jaya, 4 = Rikta, 0 = Purna.

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
The classification of Tithis into five groups (Nandā, Bhadrā, Jayā, Riktā, Pūrṇā) repeats cyclically every five days. Each group has specific qualities associated with the five elements.

Step 2: Detailed Explanation:
The cyclical sequence is:
1. Nandā: Tithis 1, 6, 11. (Associated with label II).
2. Bhadrā: Tithis 2, 7, 12. (Associated with label I).
3. Jayā: Tithis 3, 8, 13. (Associated with label IV).
4. Riktā: Tithis 4, 9, 14. (Associated with label III).
5. Pūrṇā: Tithis 5, 10, 15.

Evaluating the list:
- Pratipadā (1st) (A): This is the first Tithi, so it is Nandā (II). (A-II)
- Caturthī (4th) (B): This is the 4th Tithi, so it is Riktā (III) (Empty/Void). (B-III)
- Saptamī (7th) (C): Follow the sequence: 1(N), 2(B), 3(J), 4(R), 5(P), 6(N), 7(B). So 7th is Bhadrā (I). (C-I)
- Trayōdaśī (13th) (D): Follow: 11(N), 12(B), 13(J). So 13th is Jayā (IV). (D-IV)

Summary:
- A (1st) \(\rightarrow\) II (Nanda)
- B (4th) \(\rightarrow\) III (Rikta)
- C (7th) \(\rightarrow\) I (Bhadra)
- D (13th) \(\rightarrow\) IV (Jaya)
This mapping (A-II, B-III, C-I, D-IV) is used to select the right Tithi for specific activities. For example, Jayā tithis (like 13th) are victorious and good for starting contests.

Step 3: Final Answer:
The correct match is A-II, B-III, C-I, D-IV.