Question

Match List-I (Compound) with List-II (Hybridisation): List-I & List-II
A. \( \text{CuCl}_5^{3-} \) & I. \( sp^3d^2 \)
B. \( \text{MnCl}_5^{3-} \) & II. \( d^2sp^3 \)
C. \( \text{XeOF}_4 \) & III. \( dsp^3 \)
D. \( \text{Fe(CO)}_5 \) & IV. \( sp^3d \)
Choose the correct match:

• A. A-IV, B-III, C-I, D-II
• B. A-IV, B-III, C-II, D-I
• C. A-IV, B-I, C-III, D-II
• D. A-IV, B-II, C-III, D-I

Hint:

Count sigma bonds + lone pairs → decide hybridisation.

Answer 1

The Correct Option is A

Concept: Hybridisation depends on steric number (number of bonds + lone pairs).

Step 1: \( \text{CuCl}_5^{3-} \)
•Coordination number = 5
•Hybridisation = \( sp^3d \) \[ A \rightarrow IV \]

Step 2: \( \text{MnCl}_5^{3-} \)
•Coordination number = 5
•Hybridisation = \( dsp^3 \) \[ B \rightarrow III \]

Step 3: \( \text{XeOF}_4 \)
•Total regions = 6 (5 bonds + 1 lone pair)
•Hybridisation = \( sp^3d^2 \) \[ C \rightarrow I \]

Step 4: \( \text{Fe(CO)}_5 \)
•Coordination number = 5
•Uses inner d-orbitals
•Hybridisation = \( d^2sp^3 \) \[ D \rightarrow II \]