Question:

Match Fatty acid abbreviation with its common name.

List - IList - II
A. 10:0I. Palmitic acid
B. 12:0II. Myristic acid
C. 14:0III. Lauric acid
D. 16:0IV. Capric acid

Show Hint

Remember that palmitic acid has 16 carbon atoms, myristic acid has 14, lauric acid has 12, and capric acid has 10.
Updated On: May 26, 2026
  • A-III, B-IV, C-II, D-I
  • A-IV, B-III, C-II, D-I
  • A-IV, B-II, C-III, D-I
  • A-IV, B-I, C-II, D-III
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The Correct Option is B

Solution and Explanation

Step 1: Concept
Fatty acids are characterized by their carbon chain length and degree of saturation. The numbering system for fatty acids starts from the carboxyl end (acid) to the methyl end, indicating the number of carbon atoms in the chain.

Step 2: Meaning

The given abbreviations represent fatty acids with specific numbers of carbon atoms but no information about double bonds or saturation state is provided. Therefore, we need to match these based on their common names and typical carbon chain lengths.

Step 3: Analysis

- 10:0 (A) corresponds to a 10-carbon fatty acid. - 12:0 (B) corresponds to a 12-carbon fatty acid. - 14:0 (C) corresponds to a 14-carbon fatty acid. - 16:0 (D) corresponds to a 16-carbon fatty acid. Now, let's match these with their common names: - Palmitic Acid (I) is the most common 16-carbon saturated fatty acid. - Myristic Acid (II) is a 14-carbon saturated fatty acid. - Lauric Acid (III) is a 12-carbon saturated fatty acid. - Capric Acid (IV) is a 10-carbon saturated fatty acid. Therefore, the correct matching should be: - A: Capric Acid (IV) - B: Lauric Acid (III) - C: Myristic Acid (II) - D: Palmitic Acid (I) This matches with option B: A-IV, B-III, C-II, D-I.

Step 4: Conclusion

The correct answer is consistent with the provided options and fatty acid common names. Final Answer: (B)
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