Mass of KOH required to completely neutralise the gas is:
Show Hint
- 56 g
- 28 g
- 42 g
- 20 g
The Correct Option is B
Solution and Explanation
Reaction: $KOH + CO_{2} \rightarrow KHCO_{3}$.
Step 2: Analysis
$11.2 dm^{3}$ of $CO_{2}$ at STP weighs 22 g.
Step 3: Conclusion
$44 g$ needs $56 g$ KOH, so $22 g$ needs $28 g$ KOH.
Final Answer: (B)
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