In the oxidation of C\(_6\)H\(_5\)-CH\(_2\)-CH\(_3\) by KMnO\(_4\) the product formed is
Show Hint
- C\(_6\)H\(_5\)-CH\(_2\)-CHO
- C\(_6\)H\(_5\)-CH\(_2\)-COOH
- C\(_6\)H\(_5\)-COOH
- C\(_6\)H\(_5\)-CH\(_2\)-OH
The Correct Option is C
Solution and Explanation
KMnO\(_4\) oxidizes alkyl side chain to carboxylic acid.
Step 2: Detailed Explanation:
C\(_6\)H\(_5\)-CH\(_2\)-CH\(_3\) \(\rightarrow\) C\(_6\)H\(_5\)-COOH (benzoic acid)
Complete oxidation of side chain.
Step 3: Final Answer:
Product is benzoic acid.
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