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light of intensity 12 w m 2 is incident on 4 cm 2
Question:
Light of intensity 12 W/m\(^2\) is incident on 4 cm\(^2\) black surface. Find radiation pressure.
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Radiation pressure on a perfectly absorbing surface: \( P = \frac{I}{c} \)
AP EAPCET - 2022
AP EAPCET
Updated On:
May 19, 2025
\( 1 \times 10^{-8}\ \text{Pa} \)
\( 4 \times 10^{-8}\ \text{Pa} \)
\( 1.6 \times 10^{-7}\ \text{Pa} \)
\( 4.8 \times 10^{-7}\ \text{Pa} \)
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The Correct Option is
B
Solution and Explanation
Radiation pressure on black body: \[ P = \frac{I}{c},\quad I = 12\ \text{W/m}^2,\quad c = 3 \times 10^8 \Rightarrow P = \frac{12}{3 \times 10^8} = 4 \times 10^{-8}\ \text{Pa} \]
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