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let z 1 1 i sqrt 3 and z 2 1 i then arg left frac
Question:
Let \( z_1 = 1 + i\sqrt{3} \) and \( z_2 = 1 + i \), then \( \arg\left( \frac{z_1}{z_2} \right) \) is
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Argument of quotient = difference of arguments.
KEAM - 2019
KEAM
Updated On:
Apr 30, 2026
\( \frac{5\pi}{12} \)
\( \frac{7\pi}{12} \)
\( \frac{11\pi}{12} \)
\( \frac{3\pi}{12} \)
Not defined
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The Correct Option is
D
Solution and Explanation
Concept:
\[ \arg\left(\frac{z_1}{z_2}\right) = \arg(z_1) - \arg(z_2) \]
Step 1:
Find argument of \(z_1\). \[ z_1 = 1 + i\sqrt{3} \Rightarrow \tan \theta = \frac{\sqrt{3}}{1} = \sqrt{3} \Rightarrow \theta = \frac{\pi}{3} \]
Step 2:
Find argument of \(z_2\). \[ z_2 = 1 + i \Rightarrow \tan \theta = 1 \Rightarrow \theta = \frac{\pi}{4} \]
Step 3:
Subtract arguments. \[ \arg\left(\frac{z_1}{z_2}\right) = \frac{\pi}{3} - \frac{\pi}{4} = \frac{4\pi - 3\pi}{12} = \frac{\pi}{12} \]
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