The given equation of the hyperbola is formed by the asymptotes: \[ x + y + 1 = 0 \quad \text{and} \quad x - y + 4 = 0 \] These represent the equations of the asymptotes of the hyperbola.
Step 1: The general equation of the hyperbola is: \[ \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1 \] The asymptotes of the hyperbola are given by the equations: \[ y = \pm \frac{b}{a} x \] From the given equations of the asymptotes, we can determine the relationship between \( a \) and \( b \).
Step 2: Since the length of the latus rectum of a hyperbola is given by \( \frac{2b^2}{a} \), we calculate this using the known values of \( a \) and \( b \) based on the asymptotes.
The final result for the length of the latus rectum is \( 4\sqrt{3} \).
| List-I | List-II | ||
|---|---|---|---|
| (A) | $f(x) = \frac{|x+2|}{x+2} , x \ne -2 $ | (I) | $[\frac{1}{3} , 1 ]$ |
| (B) | $(x)=|[x]|,x \in [R$ | (II) | Z |
| (C) | $h(x) = |x - [x]| , x \in [R$ | (III) | W |
| (D) | $f(x) = \frac{1}{2 - \sin 3x} , x \in [R$ | (IV) | [0, 1) |
| (V) | { -1, 1} | ||
| List I | List II | ||
|---|---|---|---|
| (A) | $\lambda=8, \mu \neq 15$ | 1. | Infinitely many solutions |
| (B) | $\lambda \neq 8, \mu \in R$ | 2. | No solution |
| (C) | $\lambda=8, \mu=15$ | 3. | Unique solution |
The equation √5·y − √8 = 0 is the directrix of a hyperbola:
x² / a² − y² / b² = 1
and the eccentricity is e = √5 / 2.
Find the value of a.