Question:
Let $x$ be a real number such that $7x+4 < 9x+8$. Then the solution set of the inequality is:
Let $x$ be a real number such that $7x+4 < 9x+8$. Then the solution set of the inequality is:
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Remember that multiplying or dividing by a negative number reverses the inequality sign, though it wasn't needed here.
Updated On: Apr 28, 2026
- $(-\infty, -2)$
- $(-\infty, -4)$
- $(-2, \infty)$
- $[-2, \infty)$
- $[-1, \infty)$
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The Correct Option is C
Solution and Explanation
Step 1: Analysis
Start with the inequality $7x + 4 < 9x + 8$.
Step 2: Calculation
Subtract $7x$ from both sides: $4 < 2x + 8$. Subtract $8$ from both sides: $-4 < 2x$. Divide by $2$: $-2 < x$ or $x > -2$.
Step 3: Conclusion
The solution set in interval notation is $(-2, \infty)$. Final Answer: (C)
Start with the inequality $7x + 4 < 9x + 8$.
Step 2: Calculation
Subtract $7x$ from both sides: $4 < 2x + 8$. Subtract $8$ from both sides: $-4 < 2x$. Divide by $2$: $-2 < x$ or $x > -2$.
Step 3: Conclusion
The solution set in interval notation is $(-2, \infty)$. Final Answer: (C)
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