Question:
Let '\(W\)' joule be the work done to move an electric charge '\(q\)' coulomb from a place \(A\), where potential is \(-5\text{ volt}\) to another place \(B\) where potential is '\(V\)' volt. The value of '\(V\)' is
Let '\(W\)' joule be the work done to move an electric charge '\(q\)' coulomb from a place \(A\), where potential is \(-5\text{ volt}\) to another place \(B\) where potential is '\(V\)' volt. The value of '\(V\)' is
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Remember: Work = charge à potential difference.
Updated On: Apr 26, 2026
- \(Wq - 5\)
- \(\frac{q}{W} + 5\)
- \(W - \frac{5}{q}\)
- \(\frac{W}{q} - 5\)
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The Correct Option is D
Solution and Explanation
Concept:
Work done: \[ W = q(V_B - V_A) \] Step 1: Substitute values. \[ W = q(V - (-5)) \] \[ W = q(V + 5) \]
Step 2: Solve for \(V\). \[ \frac{W}{q} = V + 5 \] \[ V = \frac{W}{q} - 5 \]
Step 3: Conclusion. \[ V = \frac{W}{q} - 5 \]
Work done: \[ W = q(V_B - V_A) \] Step 1: Substitute values. \[ W = q(V - (-5)) \] \[ W = q(V + 5) \]
Step 2: Solve for \(V\). \[ \frac{W}{q} = V + 5 \] \[ V = \frac{W}{q} - 5 \]
Step 3: Conclusion. \[ V = \frac{W}{q} - 5 \]
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