Question:

Let $\vec{AB}=2\hat{i}+10\hat{j}+11\hat{k}$ and $\vec{AC}=-\hat{i}+2\hat{j}+2\hat{k}$. If $\theta$ is the angle between $\vec{AB}$ and $\vec{AC}$, then $\sin\theta=$ ________.

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$\sin^2\theta + \cos^2\theta = 1$.
Updated On: Jun 26, 2026
  • $\frac{\sqrt{13}}{9}$
  • $\frac{\sqrt{15}}{9}$
  • $\frac{\sqrt{14}}{9}$
  • $\frac{\sqrt{17}}{9}$
  • $\frac{4}{9}$
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The Correct Option is D

Solution and Explanation

Step 1: Concept
Use the dot product to find $\cos\theta$, then find $\sin\theta$.

Step 2: Meaning

$\vec{AB} \cdot \vec{AC} = (2)(-1) + (10)(2) + (11)(2) = -2 + 20 + 22 = 40$.
$|\vec{AB}| = \sqrt{4+100+121} = 15$. $|\vec{AC}| = \sqrt{1+4+4} = 3$.

Step 3: Analysis

$\cos\theta = \frac{40}{15 \times 3} = \frac{40}{45} = \frac{8}{9}$.
$\sin\theta = \sqrt{1 - \cos^2\theta} = \sqrt{1 - \left(\frac{8}{9}\right)^2} = \sqrt{1 - \frac{64}{81}} = \sqrt{\frac{17}{81}}$.

Step 4: Conclusion

$\sin\theta = \frac{\sqrt{17}}{9}$. Final Answer: (D)
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