Let \( p, q, r \) be three simple statements. Then \( \sim(p \lor q) \lor \sim(p \lor r) \equiv \)
Show Hint
When simplifying logical expressions, think of $\land$ like multiplication and $\lor$ like addition. Factoring out common terms (Distributive Law) is often the fastest way to reach the simplified form.
Concept:
This problem involves De Morgan's Laws and the Distributive Law of logical equivalence.
• De Morgan's Law: $\sim(a \lor b) \equiv \sim a \land \sim b$.
• Distributive Law: $(a \land b) \lor (a \land c) \equiv a \land (b \lor c)$.
Step 1: Apply De Morgan's Law to each component.
The given expression is $\sim(p \lor q) \lor \sim(p \lor r)$.
Applying $\sim(A \lor B) \equiv \sim A \land \sim B$:
\[
\sim(p \lor q) \equiv \sim p \land \sim q
\]
\[
\sim(p \lor r) \equiv \sim p \land \sim r
\]
So the expression becomes:
\[
(\sim p \land \sim q) \lor (\sim p \land \sim r)
\]
Step 2: Apply the Distributive Law.
Notice that $\sim p$ is a common factor in both terms joined by an OR ($\lor$):
\[
(\sim p \land \sim q) \lor (\sim p \land \sim r) \equiv \sim p \land (\sim q \lor \sim r)
\]