Question:

Let $f(x)=[x]$, $x\in(0,6)$, where $[x]$ is the greatest integer function. Then the number of discontinuities of $f(x)$ is:

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For an open interval $(a, b)$, the number of discontinuities of $[x]$ is $\lfloor b - \epsilon \rfloor - \lfloor a \rfloor$, effectively counting integers between $a$ and $b$.
Updated On: Apr 28, 2026
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The Correct Option is

Solution and Explanation

Step 1: Concept
The greatest integer function $[x]$ is discontinuous at every integer point.

Step 2: Analysis

The interval given is $0 < x < 6$. The integers within this open interval are $\{1, 2, 3, 4, 5\}$.

Step 3: Conclusion

There are 5 such integer points where the function jumps. Hence, there are 5 points of discontinuity. Final Answer: (E)
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