Let \( f(x) = \sqrt{4 - x^2} \), \( g(x) = \sqrt{x^2 - 1} \). Then the domain of the function \( h(x) = f(x) + g(x) \) is equal to:
The domain of \( f(x) = \sqrt{4 - x^2} \) is \( -2 \leq x \leq 2 \), and the domain of \( g(x) = \sqrt{x^2 - 1} \) is \( x \leq -1 \) or \( x \geq 1 \). For the function \( h(x) = f(x) + g(x) \) to be defined, the domain must satisfy both conditions: Thus, the domain of \( h(x) \) is \( [-2, 1] \cup [1, 2] \).
Thus, the correct answer is (D).
If $ | \vec{a} | = 3 $, $ | \vec{b} | = 2 $, then find $ (3\vec{a} - 2\vec{b}) \cdot (3\vec{a} + 2\vec{b}) $.
If $ | \vec{a} | = 3 $, $ | \vec{b} | = 2 $, then find $ (3\vec{a} - 2\vec{b}) \cdot (3\vec{a} + 2\vec{b}) $.