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let f x px 2 qx r where p q r are constants and p
Question:
Let \( f(x) = px^2 + qx + r \), where \( p,q,r \) are constants and \( p \neq 0 \). If \( f(5) = -3f(2) \) and \( f(-4) = 0 \), then the other root of \( f \) is
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Use given root condition to reduce unknowns in quadratic equations.
KEAM - 2018
KEAM
Updated On:
May 1, 2026
\( 3 \)
\( -7 \)
\( -2 \)
\( 2 \)
\( 6 \)
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The Correct Option is
A
Solution and Explanation
Concept:
If one root is known, use: \[ \alpha + \beta = -\frac{q}{p} \]
Step 1:
Given \( f(-4)=0 \Rightarrow -4 \) is a root.
Step 2:
Use condition: \[ f(5) = -3f(2) \] Substitute: \[ 25p +5q + r = -3(4p +2q + r) \]
Step 3:
Simplify.
\[ 25p +5q + r = -12p -6q -3r \] \[ 37p +11q +4r = 0 \]
Step 4:
Using root \( -4 \):
\[ 16p -4q + r = 0 \]
Step 5:
Solve system → find ratio of coefficients → other root = 3.
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