Step 1: Find the first derivative of \( f(x) \).
\[
f'(x) = 20x + e^x - 2\cos(2x) + \sin x
\]
We set \( f'(x) = 0 \) to find the critical points.
Step 2: Analyze the second derivative.
The second derivative is:
\[
f''(x) = 20 + e^x + 4\sin(2x) + \cos x
\]
To find the points where \( f(x) \) has a local minimum, check where \( f''(x)>0 \).
Step 3: Conclusion.
By solving these equations and analyzing the second derivative, we conclude that \( f(x) \) has 1 point of local minimum.
Final Answer:
\[
\boxed{1}
\]