Question:

Let \( f:\mathbb{R} \to \mathbb{R} \) be a differentiable function. If \( f \) is even, then \( f'(0) \) is equal to

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Derivative of an even function is always an odd function, so value at 0 must be zero.
Updated On: May 1, 2026
  • 1
  • 2
  • 0
  • -1
  • \( \frac{1}{2} \)
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The Correct Option is C

Solution and Explanation

Concept: For an even function: \[ f(-x) = f(x) \] Differentiating both sides: \[ -f'(-x) = f'(x) \Rightarrow f'(-x) = -f'(x) \] So derivative of even function is odd.

Step 1:
Apply property at \( x = 0 \).
\[ f'(0) = -f'(0) \]

Step 2:
Solve.
\[ 2f'(0) = 0 \Rightarrow f'(0) = 0 \] Final Answer: \[ 0 \]
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