Let $A(-1,\,2)$, $B(1,\,-2)$ and $C(-2,\,-2)$ be vertices of the triangle $ABC$. The equation of the line passing through $C$ and parallel to $AB$ is
Show Hint
Parallel lines have equal slopes. Once you find the slope of the reference line, directly apply point-slope form with the given point to get the parallel line's equation.
Step 1: Understanding the Concept:
A line parallel to $AB$ has the same slope as $AB$. Use point-slope form with point $C$. Step 2: Detailed Explanation:
Slope of $AB = \dfrac{-2-2}{1-(-1)} = \dfrac{-4}{2} = -2$.
Line through $C(-2,\,-2)$ with slope $-2$:
\[
y - (-2) = -2(x - (-2)) \implies y + 2 = -2x - 4 \implies 2x + y + 6 = 0
\] Step 3: Final Answer:
The required equation is $2x + y + 6 = 0$.