Question:

Let $A(-1,\,2)$, $B(1,\,-2)$ and $C(-2,\,-2)$ be vertices of the triangle $ABC$. The equation of the line passing through $C$ and parallel to $AB$ is

Show Hint

Parallel lines have equal slopes. Once you find the slope of the reference line, directly apply point-slope form with the given point to get the parallel line's equation.
Updated On: Apr 25, 2026
  • $x + 2y + 6 = 0$
  • $2x - y + 6 = 0$
  • $2x + y - 6 = 0$
  • $2x - y - 6 = 0$
  • $2x + y + 6 = 0$
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The Correct Option is

Solution and Explanation

Step 1: Understanding the Concept:
A line parallel to $AB$ has the same slope as $AB$. Use point-slope form with point $C$.

Step 2:
Detailed Explanation:
Slope of $AB = \dfrac{-2-2}{1-(-1)} = \dfrac{-4}{2} = -2$.
Line through $C(-2,\,-2)$ with slope $-2$:
\[ y - (-2) = -2(x - (-2)) \implies y + 2 = -2x - 4 \implies 2x + y + 6 = 0 \]

Step 3:
Final Answer:
The required equation is $2x + y + 6 = 0$.
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