Length of an organ pipe open at both ends is 34 cm. If velocity of sound is 340 m/s, then the frequency of 2nd overtone is:
Show Hint
In an organ pipe open at both ends, the harmonics are integer multiples of the fundamental frequency, with the second overtone being the third harmonic.
Step 1: Frequency of Harmonics in an Organ Pipe.
The frequency of the \( n \)-th harmonic in an open organ pipe is given by:
\[
f_n = \frac{n v}{2L}
\]
where \( v \) is the velocity of sound and \( L \) is the length of the pipe. The second overtone corresponds to the third harmonic. Substituting the values:
\[
f_3 = \frac{3 \times 340}{2 \times 0.34} = 1500 \, \text{Hz}
\]
Step 2: Final Answer.
Thus, the frequency of the second overtone is 1500 Hz.