Length of an arc of a sector of angle 45° when the radius of the circle is 3 cm, is:
Step 1: Formula for the Length of an Arc. The length \( L \) of an arc of a sector is given by the formula: \[ L = \frac{\theta}{360} \times 2\pi r \] where \( \theta \) is the central angle, and \( r \) is the radius of the circle.
Step 2: Substituting the Given Values. Here, the radius \( r = 3 \, \text{cm} \) and the angle \( \theta = 45^\circ \). Substituting these values into the formula, we get: \[ L = \frac{45}{360} \times 2 \times 3.14 \times 3 \] \[ L = \frac{45}{360} \times 18.84 = \frac{1}{8} \times 18.84 \] \[ L = \frac{3\pi}{4} \, \text{cm} \]
Step 3: Conclusion. Thus, the length of the arc is \( \frac{3\pi}{4} \, \text{cm} \).
What is the diameter of the circle in the figure ? 
Consider the above figure and read the following statements.
Statement 1: The length of the tangent drawn from the point P to the circle is 24 centimetres. If OP is 25 centimetres, then the radius of the circle is 7 centimetres.
Statement 2: A tangent to a circle is perpendicular to the radius through the point of contact.
Now choose the correct answer from those given below. 