Question:
\(KMnO_4\) is prepared from Mn(II) ion salts by oxidizing it with
\(KMnO_4\) is prepared from Mn(II) ion salts by oxidizing it with
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Peroxodisulphate (\(S_2O_8^{2-}\)) is a powerful oxidizing agent.
Updated On: Apr 24, 2026
- \(KClO_3\)
- \(K_2S_2O_8\)
- \(KNO_3\)
- \(KClO_4\)
- \(KOH\)
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The Correct Option is B
Solution and Explanation
Concept:
Strong oxidizing agents are required to convert Mn(II) to Mn(VII) in \(KMnO_4\).
Step 1: Identify oxidizing agent.
• \(K_2S_2O_8\) is a strong oxidizing agent
• It can oxidize Mn\(^{2+}\) to Mn\(^{7+}\)
Step 2: Select correct option.
\[ K_2S_2O_8 \text{ is used in preparation of } KMnO_4 \]
Step 1: Identify oxidizing agent.
• \(K_2S_2O_8\) is a strong oxidizing agent
• It can oxidize Mn\(^{2+}\) to Mn\(^{7+}\)
Step 2: Select correct option.
\[ K_2S_2O_8 \text{ is used in preparation of } KMnO_4 \]
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