Question:
\(\displaystyle \int \sec^{2}4x\,dx=\) ?
\(\displaystyle \int \sec^{2}4x\,dx=\) ?
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Differentiate to verify: $\left(\frac{1}{a}\tan ax\right)'=\sec^{2}ax$.
Updated On: Oct 17, 2025
- \(\tan4x+k\)
- \(\dfrac14\tan4x+k\)
- \(4\tan4x+k\)
- \(8\tan4x+k\)
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The Correct Option is B
Solution and Explanation
\(\displaystyle \int \sec^{2}(ax)\,dx=\frac{1}{a}\tan(ax)+C\). With \(a=4\), answer is \(\frac14\tan4x+k\).
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