Question:

\( \int \frac{2x^2 + 4x + 3}{x^2 + x + 1} \, dx = \)

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Always try division when numerator degree $\ge$ denominator degree.
Updated On: Apr 21, 2026
  • \( 2\log_e|x^2+x+1| + C \)
  • \( x\log_e|x^2+x+1| + C \)
  • \( \frac{1}{2}\log_e|x^2+x+1| + C \)
  • \( 2x + \log_e|x^2+x+1| + C \)
  • \( x + 2\log_e|x^2+x+1| + C \)
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The Correct Option is D

Solution and Explanation

Concept: Split into: \[ \frac{2x^2+4x+3}{x^2+x+1} = 2 + \frac{2x+1}{x^2+x+1} \]

Step 1:
Split integral.
\[ \int 2\,dx + \int \frac{2x+1}{x^2+x+1}dx \]

Step 2:
Solve.
\[ = 2x + \log|x^2+x+1| + C \]
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