Question:

Infinite number of masses, each 1kg, are placed along the x-axis at x=±1m, ±2m, ±4m, ±8m, …. The magnitude of the resultant gravitational potential at the origin is:

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Use geometric series for infinite mass distributions.
Updated On: Mar 20, 2026
  • \( \dfrac{G}{2} \)
  • \( G \)
  • \( 2G \)
  • 4G
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The Correct Option is D

Solution and Explanation


Step 1:
Potential due to one mass at distance r: V = -(G)/(r)
Step 2:
Sum of reciprocals: (1 + (1)/(2) + (1)/(4) + ⋯ ) = 2
Step 3:
Considering both sides: V = -2G × 2 = -4G
Step 4:
Magnitude = 4G.
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