Question

Increasing order of solubility of AgCl in:

• (i) H₂O
• (ii) 1M NaCl (aq)
• (iii) 1M CaCl₂ (aq)
• (iv) 1M NaNO₃ (aq)

• A. CaCl₂<NaCl<H₂O<NaNO₃
• B. CaCl₂>H₂O>NaCl>NaNO₃
• C. CaCl₂>NaCl>H₂O<NaNO₃
• D. CaCl₂<NaCl<H₂O>NaNO₃

Hint:

In solubility problems, remember the effect of the common ion on solubility. The presence of ions like Na^{+ and Cl^{- from NaCl or CaCl\textsubscript{2 will generally decrease the solubility of AgCl due to the common ion effect. Non-electrolytes like NaNO\textsubscript{3 have minimal effect on solubility.

Answer 1

The Correct Option is D

We are given the compounds AgCl, NaCl, and CaCl₂ in various solvents.

To determine the order of solubility, consider the following:

- AgCl is sparingly soluble in water, but the presence of ions like NaCl or CaCl₂ can reduce its solubility due to the common ion effect.

- CaCl₂ dissociates into Ca²⁺ and Cl^- ions, which can shift the equilibrium and increase the solubility of AgCl.

- NaNO₃ does not participate in the common ion effect and will have minimal interference with the solubility of AgCl.

Therefore, the increasing order of solubility is:

\(\text{CaCl}_2<\text{NaCl}<\text{H}_2\text{O}<\text{NaNO}_3\)