Question

Increasing order of rms velocities of \( \text{H}_2 \), \( \text{O}_2 \), \( \text{N}_2 \) and \( \text{HBr} \) is

• A. \( \text{H}_2 \) \( \rightarrow \text{O}_2 \) \( \rightarrow \text{N}_2 \) \( \rightarrow \text{HBr} \)
• B. \( \text{H}_2 \) \( \rightarrow \text{N}_2 \) \( \rightarrow \text{O}_2 \) \( \rightarrow \text{HBr} \)
• C. \( \text{H}_2 \) \( \rightarrow \text{O}_2 \) \( \rightarrow \text{HBr} \) \( \rightarrow \text{N}_2 \)
• D. \( \text{HBr} \) \( \rightarrow \text{N}_2 \) \( \rightarrow \text{H}_2 \) \( \rightarrow \text{O}_2 \)

Hint:

The rms velocity of a gas is inversely proportional to the square root of its molar mass.

Answer 1

The Correct Option is B

Step 1: Use the formula for rms velocity.
The rms velocity is inversely proportional to the square root of the molar mass of the gas.
Step 2: Conclusion.
The increasing order of rms velocities is \( \text{H}_2 \), \( \text{N}_2 \), \( \text{O}_2 \), and \( \text{HBr} \). Final Answer: \[ \boxed{\text{H}_2 \rightarrow \text{N}_2 \rightarrow \text{O}_2 \rightarrow \text{HBr}} \]