Question:

 In the first configuration (1) as shown in the figure, four identical charges \( q_0 \) are kept at the corners A, B, C and D of square of side length \( a \). In the second configuration (2), the same charges are shifted to mid points C, E, H, and F of the square. If \( K = \frac{1}{4\pi \epsilon_0} \), the difference between the potential energies of configuration (2) and (1) is given by:

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To solve problems involving potential energy, use the formula for the potential energy between two charges and sum over all pairs of charges. Pay attention to the distances between the charges in different configurations.
Updated On: Mar 25, 2026
  • \( \frac{Kq_0^2}{a} (4\sqrt{2} - 2) \)
  • \( \frac{Kq_0^2}{a} (4 - \sqrt{2}) \)
  • \( \frac{Kq_0^2}{a} (3\sqrt{2} - 2) \)
  • \( \frac{Kq_0^2}{a} (3 - \sqrt{2}) \)
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The Correct Option is A

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