Question:

In which one of the following pairs the radius of the second species is greater than that of the first?

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In which one of the following pairs the radius of the second species is greater than that of the first?
Updated On: Apr 15, 2026
  • Na, Mg
  • $O^{2-}, N^{3-}$
  • $Li^{+}, Be^{2+}$
  • $Ba^{2+}, Sr^{2+}$
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The Correct Option is B

Solution and Explanation

Step 1: Concept
$O^{2-}$ and $N^{3-}$ are isoelectronic species (same number of electrons).
Step 2: Analysis
For isoelectronic ions, as the negative charge increases, the ionic radius increases.
Step 3: Conclusion
The electrons are held less tightly by the nucleus in $N^{3-}$, making its radius greater than $O^{2-}$.
Final Answer: (B)
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