Question:
In which of the following reactions, chlorine undergoes disproportionation?
\[
\begin{aligned}
\text{I.} \quad & \text{Reaction with cold, dilute NaOH} \\
\text{II.} \quad & \text{Reaction with hot, concentrated NaOH} \\
\text{III.} \quad & \text{Reaction with } \mathrm{H_2S}
\end{aligned}
\]
The correct answer is
In which of the following reactions, chlorine undergoes disproportionation?
\[
\begin{aligned}
\text{I.} \quad & \text{Reaction with cold, dilute NaOH} \\
\text{II.} \quad & \text{Reaction with hot, concentrated NaOH} \\
\text{III.} \quad & \text{Reaction with } \mathrm{H_2S}
\end{aligned}
\]
The correct answer is
Show Hint
Chlorine undergoes disproportionation in alkaline medium:
\[
\mathrm{Cl_2 \rightarrow Cl^- + ClO^-}
\]
(cold, dilute NaOH)
\[
\mathrm{Cl_2 \rightarrow Cl^- + ClO_3^-}
\]
(hot, concentrated NaOH)
Updated On: Jul 9, 2026
- I, II only
- I, II, III
- III only
- II only \bigskip
Show Solution
Verified By Collegedunia
The Correct Option is A
Solution and Explanation
Step 1: Reaction with cold, dilute NaOH.
\[
\mathrm{Cl_2+2NaOH
\rightarrow
NaCl+NaOCl+H_2O}
\]
Here, chlorine changes from oxidation state \(0\) to \(-1\) and \(+1\).
Hence, disproportionation occurs.
Step 2: Reaction with hot, concentrated NaOH. \[ 3\mathrm{Cl_2}+6\mathrm{NaOH} \rightarrow 5\mathrm{NaCl}+\mathrm{NaClO_3}+3\mathrm{H_2O} \] Chlorine changes from \(0\) to \(-1\) and \(+5\). Hence, disproportionation also occurs.
Step 3: Reaction with \(\mathrm{H_2S}\). \[ \mathrm{Cl_2+H_2S \rightarrow 2HCl+S} \] Chlorine is only reduced from \(0\) to \(-1\), so no disproportionation occurs.
Step 4: Final conclusion. Disproportionation occurs only in reactions I and II. Hence, the correct option is \[ \boxed{(A)} \]
Step 2: Reaction with hot, concentrated NaOH. \[ 3\mathrm{Cl_2}+6\mathrm{NaOH} \rightarrow 5\mathrm{NaCl}+\mathrm{NaClO_3}+3\mathrm{H_2O} \] Chlorine changes from \(0\) to \(-1\) and \(+5\). Hence, disproportionation also occurs.
Step 3: Reaction with \(\mathrm{H_2S}\). \[ \mathrm{Cl_2+H_2S \rightarrow 2HCl+S} \] Chlorine is only reduced from \(0\) to \(-1\), so no disproportionation occurs.
Step 4: Final conclusion. Disproportionation occurs only in reactions I and II. Hence, the correct option is \[ \boxed{(A)} \]
Was this answer helpful?
0
0
Top AP EAPCET Chemistry Questions
- The four quantum numbers of the valence electron of potassium are :
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
- In which of the following the election gain enthalpy of elements is correctly arranged?
- The radii of $ \text{F,}{{\text{F}}^{-}}\text{O} $ and $ {{\text{O}}^{2-}} $ are in the order
- Which of the following has the highest first ionization potential?
View More Questions
Top AP EAPCET Questions
- A body is projected from the ground at an angle of $\tan^{-1} \left( \frac{8}{7}\right)$ with the horizontal. The ratio of the maximum height attained by it to its range is
- The four quantum numbers of the valence electron of potassium are :
- A lens forms real and virtual images of an object, when the object is at $u_{1}$ and $u_{2}$ distances respectively. If the size of the virtual image is double that of the real image, then the focal length of the lens is (take, the magnification of the real image as $m$ )
- Two spheres $P$ and $Q$, each of mass $200\, g$ are attached to a string of length one metre as shown in the figure. The string and the spheres are then whirled in a horizontal circle about $O$ at a constant angular speed. The ratio of the tension in the string between $P$ and $Q$ to that of between $P$ and $O$ is $(P$ is at mid-point of the line joining $O$ and $Q$ )
- The volume of $0.02\, M$ acidified permanganate solution required for complete reaction of $60\, mL$ of $0.01\, MI^{-}$ ion solution to form $I_2$ in $mL$ is
View More Questions