To determine whether molecules possess a dipole moment, we need to consider their molecular geometry and the electronegativity difference between atoms.
1. \( SO_2 \) (Sulfur dioxide):
- Molecular shape: Bent (angular)
- The S–O bonds are polar due to electronegativity difference.
- The bent shape means the bond dipoles do not cancel out.
- Hence, \( SO_2 \) has a net dipole moment.
2. \( NF_3 \) (Nitrogen trifluoride):
- Molecular shape: Trigonal pyramidal (like ammonia)
- N–F bonds are polar.
- The lone pair on nitrogen causes the bond dipoles to not cancel completely.
- Therefore, \( NF_3 \) has a net dipole moment, though smaller than ammonia.
Therefore, in the pair \( SO_2 \) and \( NF_3 \), both molecules possess dipole moments.
Hence, the correct answer is:
\( SO_2, NF_3 \)