Question:

In which of the following equilibrium reaction, pressure does not influence the equilibrium at constant temperature?}

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If total gaseous moles are equal on both sides, changing pressure does not shift equilibrium.
Updated On: Apr 24, 2026
  • \(H_2(g) + I_2(g) \rightleftharpoons 2HI(g)\)
  • \(N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g)\)
  • \(PCl_5(g) \rightleftharpoons PCl_3(g) + Cl_2(g)\)
  • \(2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g)\)
  • \(2N_2O_5(g) \rightleftharpoons 4NO_2(g) + O_2(g)\)
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The Correct Option is A

Solution and Explanation

Pressure affects gaseous equilibrium only when the total number of moles of gas changes. Check option (A): \[ H_2 + I_2 \rightleftharpoons 2HI \] Reactant gas moles: \[ 1+1=2 \] Product gas moles: \[ 2 \] Since the number of gaseous moles is same on both sides, pressure has no effect.
Hence, the correct answer is: \[ \boxed{(A)} \]
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