Question

In which of the following case, does the reaction go farthest to completion?

• A. \(K = 10^2\)
• B. \(K = 10\)
• C. \(K = 10^{-2}\)
• D. \(K = 1\)

Hint:

Greater the equilibrium constant, more the products formed. \(K \gg 1\) means reaction almost goes to completion.

Answer 1

The Correct Option is A

Step 1: Meaning of equilibrium constant.
If \(K\) is very large (\(K \gg 1\)), equilibrium lies far to the right, meaning products dominate.
If \(K \ll 1\), reactants dominate.
Step 2: Compare values.
\[ 10^2 = 100,\quad 10,\quad 10^{-2}=0.01,\quad 1 \] Largest value is \(100\).
Step 3: Conclusion.
So reaction goes farthest to completion when \(K = 10^2\).
Final Answer: \[ \boxed{K = 10^2} \]