Question:

In which of the following carbohydrate, molecular mass increases by 84u after complete acetylation?

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Chemistry Tip: Number of acetyl groups introduced = number of hydroxyl groups present.
Updated On: Apr 23, 2026
  • Aldotriose
  • Aldotetrose
  • Ketotetrose
  • Ketopentose
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The Correct Option is A

Solution and Explanation

Step 1: Understand acetylation. During acetylation, each hydroxyl group $(-OH)$ is converted into acetate group $(-OCOCH_3)$. Net increase in mass for one hydroxyl group is: $$ CH_3CO - H = 43 - 1 = 42u $$ So, each $-OH$ group increases molecular mass by $42u$.

Step 2: Total increase given.
Total increase in mass after complete acetylation: $$ 84u $$

Step 3: Find number of hydroxyl groups.
$$ \text{Number of } -OH \text{ groups}=\frac{84}{42}=2 $$

Step 4: Identify carbohydrate with two hydroxyl groups.
Aldotriose structure: $$ CHO-CHOH-CH_2OH $$ It contains exactly two hydroxyl groups.

Step 5: Conclusion.
Hence the carbohydrate must be aldotriose. $$ \therefore \text{Correct option is (A) Aldotriose.} $$
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