Question:

In triangle ABC, with usual notations, if \(a = 4,b = 5\) and \(c = 6\), then angle C is equal to...

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Find cos A and cos C by the cosine rule and compare cos 2A with cos C.
Updated On: Oct 1, 2026
  • \(A\)
  • \(2A\)
  • \(3A\)
  • \(\frac{A}{2}\)
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The Correct Option is B

Solution and Explanation

Step 1: Cosine of C
\(\cos C = \frac{a^2+b^2-c^2}{2ab} = \frac{16+25-36}{40} = \frac18\).

Step 2: Cosine of A
\(\cos A = \frac{b^2+c^2-a^2}{2bc} = \frac{25+36-16}{60} = \frac34\).

Step 3: Double angle
\(\cos2A = 2\cos^2A - 1 = 2\cdot\frac{9}{16} - 1 = \frac18\).

Step 4: Compare
\(\cos2A = \cos C\) and both angles lie in the range where cosine is one-to-one, so \(C = 2A\). Option (B).

Final Answer:
Angle C equals 2A. \[ \boxed{\text{(B)}\ C = 2A} \]
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