Question

In thermodynamic isobaric process

• A. change in internal energy is zero
• B. work done is zero
• C. change in internal energy is not zero
• D. heat supplied is zero

Hint:

Pressure is constant, but temperature and volume change.

Answer 1

The Correct Option is C

Step 1: Understanding the Concept:
An isobaric process occurs at constant pressure. Gas is allowed to expand or contract, so work is done, and heat is exchanged.

Step 2: Apply the first law:
\(Q=\Delta U+W\). In an isobaric process, \(W=P\Delta V\ne0\), and \(Q=nC_p\Delta T\). The internal energy change is \(\Delta U=nC_v\Delta T\), which is non-zero whenever the temperature changes.

Step 3: Check the options:
(A) \(\Delta U=0\) is true for an isothermal process. (B) \(W=0\) is true for an isochoric process. (D) \(Q=0\) is true for an adiabatic process. (C) \(\Delta U\ne0\) is the isobaric case.

Step 4: Choose:
Option (C).

Final Answer:
In an isobaric process the internal energy changes. \[ \boxed{C} \]