Step 1: Understanding the wave equation.
The given wave equation is:
\[ y = 3 \cos \pi (100t - x) \] This is a standard wave equation of the form: \[ y = A \cos(kx - \omega t) \] where \( k \) is the wave number and \( \omega \) is the angular frequency.
Step 2: Identifying the wavelength.
In the equation \( y = 3 \cos \pi (100t - x) \), comparing it with the standard form, we see that \( k = \pi \). The relationship between the wave number \( k \) and the wavelength \( \lambda \) is: \[ k = \frac{2\pi}{\lambda} \] Thus: \[ \pi = \frac{2\pi}{\lambda} \quad \Rightarrow \quad \lambda = 2 \, \text{cm} \] Thus, the correct answer is
(A) 2 cm.
The equivalent capacitance of the circuit given between A and B is 
The value of current $ I $ in the adjoining circuit will be 
Let the function $ f(x) $ be defined as follows: $$ f(x) = \begin{cases} (1 + | \sin x |)^{\frac{a}{|\sin x|}}, & -\frac{\pi}{6}<x<0 \\b, & x = 0 \\ \frac{\tan 2x}{\tan 3x}, & 0<x<\frac{\pi}{6} \end{cases} $$ Then the values of $ a $ and $ b $ are: