Question:

In the series LCR circuit shown in figure, the impedance is

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- $Z = \sqrt{R^2 + (X_L - X_C)^2}$ - Always compute $\omega = 2\pi f$ first
Updated On: May 4, 2026
  • \(300\,\Omega\)
  • \(500\,\Omega\)
  • \(700\,\Omega\)
  • \(900\,\Omega\)
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The Correct Option is B

Solution and Explanation

Given:
\[ L = 1\,\text{H}, \quad C = 20\,\mu\text{F} = 20 \times 10^{-6}\,\text{F}, \quad R = 300\,\Omega \] \[ f = \frac{50}{\pi}\,\text{Hz} \]

Step 1: Angular frequency

\[ \omega = 2\pi f = 2\pi \cdot \frac{50}{\pi} = 100\,\text{rad/s} \]

Step 2: Inductive reactance

\[ X_L = \omega L = 100 \times 1 = 100\,\Omega \]

Step 3: Capacitive reactance

\[ X_C = \frac{1}{\omega C} = \frac{1}{100 \times 20 \times 10^{-6}} = \frac{1}{2 \times 10^{-3}} = 500\,\Omega \]

Step 4: Net reactance

\[ X = X_L - X_C = 100 - 500 = -400\,\Omega \]

Step 5: Impedance

\[ Z = \sqrt{R^2 + X^2} = \sqrt{300^2 + 400^2} = \sqrt{90000 + 160000} = \sqrt{250000} = 500\,\Omega \]
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