Question

In the oxidation of phosphorus with oxygen, 0.2 mol of P₄ produces ____ g of P₄O₁₀.
(rounded off to one decimal place) 
[Given: Atomic weight of P = 31; Atomic weight of O = 16]

Answer 1

Correct Answer: 56.7 - 56.9

The molecular weight of PO can be calculated from the atomic weights of phosphorus (P) and oxygen (O). The molar mass of PO is:

\(M_{PO} = (4 \times \text{atomic weight of P}) + (10 \times \text{atomic weight of O})\)

\(M_{PO} = (4 \times 31) + (10 \times 16) = 124 + 160 = 284 \text{ g/mol}\)

Now, if 0.2 mol of P produces PO, the mass of PO produced is:

\(\text{mass of PO} = 0.2 \text{ mol} \times 284 \text{ g/mol} = 56.8 \text{ g}\)

Thus, the mass of PO produced is 56.8 g