Question

The amount of ethane produced in the following reaction is kg.

(round off to two decimal places)

Answer 1

Correct Answer: 1.92 - 1.93

The balanced chemical reaction is:

C₂H₄ + H₂ → C₂H₆ (90% catalytic conversion)

Step 1: Determine the moles of reactants

• Molar mass of C₂H₄ = 28 g/mol
• Molar mass of H₂ = 2 g/mol
• Moles of C₂H₄ = (2000 g)/(28 g/mol) ≈ 71.43 mol
• Moles of H₂ = (2000 g)/(2 g/mol) = 1000 mol

 

Step 2: Identify the limiting reactant

• For full conversion, 71.43 mol of C₂H₄ requires 71.43 mol of H₂.
• C₂H₄ is the limiting reactant since all of it reacts first.

 

Step 3: Calculate the moles of C₂H₆ produced

• Moles of C₂H₆ = 71.43 mol (90% conversion) = 71.43 * 0.90 ≈ 64.29 mol

 

Step 4: Calculate the mass of C₂H₆ produced

• Molar mass of C₂H₆ = 30 g/mol
• Mass of C₂H₆ = 64.29 mol * 30 g/mol = 1928.57 g = 1.93 kg

 

The mass of ethane produced is 1.93 kg.