Question:

In the hydrogen atomic spectrum, the emission of the least energetic photon takes place during the transition from $n=6$ energy level to $n = $ _____ energy level.

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Closer energy levels → lower energy photon emitted.
Updated On: May 2, 2026
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The Correct Option is C

Solution and Explanation

Concept: Energy transitions in hydrogen atom
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Step 1: Energy formula

\[ E_n = -\frac{13.6}{n^2} \text{ eV} \] Energy difference: \[ \Delta E = E_f - E_i \] ---

Step 2: Least energetic photon

Smallest energy difference occurs when levels are closest. Thus transition: \[ 6 \rightarrow 5 \] ---

Step 3: Compare options


• $6 \rightarrow 1$ → large energy ❌
• $6 \rightarrow 2$ → large ❌
• $6 \rightarrow 3$ → moderate ❌
• $6 \rightarrow 4$ → smaller ❌
• $6 \rightarrow 5$ → smallest ✅ --- Final Answer: \[ \boxed{5} \]
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