Question:
In the given sequence of reactions:
\[
\text{P}_4 + \text{NaOH} + \text{H}_2\text{O} \;\longrightarrow\; \dots \;\longrightarrow\; X \;+\; 2\,\text{NaH}_2\text{PO}_2 \;\longrightarrow\; \dots
\]
The final product obtained with copper and \(\text{H}_2\text{SO}_4\) is:
In the given sequence of reactions:
\[
\text{P}_4 + \text{NaOH} + \text{H}_2\text{O} \;\longrightarrow\; \dots \;\longrightarrow\; X \;+\; 2\,\text{NaH}_2\text{PO}_2 \;\longrightarrow\; \dots
\]
The final product obtained with copper and \(\text{H}_2\text{SO}_4\) is:
Show Hint
Phosphine (PH\(_3\)) can reduce certain metal salts to metal phosphides.
- In an acidic medium with copper, phosphide formation is common.
Updated On: Mar 6, 2026
- \(\text{Cu}_3(\text{PO}_4)_2\)
- \(\text{Cu}_3\text{P}_2\)
- \(\text{Cu}(\text{OH})_2\)
- \(\text{CuCO}_3\)
Show Solution
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The Correct Option is B
Solution and Explanation
Step 1: Reactions of Phosphorus with Alkali - White phosphorus (\(\text{P}_4\)) reacts with \(\text{NaOH}\) and water to give phosphine (\(\text{PH}_3\)) and hypophosphite (\(\text{NaH}_2\text{PO}_2\)).
Step 2: Reaction with Copper and Acid - Phosphine can further react under specific conditions (involving \(\text{Cu}\) and \(\text{H}_2\text{SO}_4\)) to produce copper phosphide, \(\text{Cu}_3\text{P}_2\). Hence, the final product is (copper phosphide), \(\text{Cu}_3\text{P}_2\).
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