In the given figure, if \( ST \parallel QR \), \( QS = 3 \text{ cm} \), \( SR = 1.5 \text{ cm} \), and \( PT = 2.8 \text{ cm} \), then find the value of \( TR \).
Show Hint
In problems involving parallel lines in triangles, use the Basic Proportionality Theorem: ratios of corresponding sides are equal.
Step 1: Concept used (Basic Proportionality Theorem).
According to the BPT (Thales’ Theorem), if a line is drawn parallel to one side of a triangle to intersect the other two sides, it divides those sides in the same ratio.
Step 2: Apply BPT.
\[
\frac{QS}{SR} = \frac{PT}{TR}
\]
Step 3: Substitute given values.
\[
\frac{3}{1.5} = \frac{2.8}{TR}
\]
\[
2 = \frac{2.8}{TR}
\]
Step 4: Solve for \( TR \).
\[
TR = \frac{2.8}{2} = 1.4 \text{ cm}
\]
Step 5: Conclusion.
Therefore, the value of \( TR \) is \( \boxed{1.4\ \text{cm}} \).