Question

In the following circuit, what is the voltage across PQ?

• A. \( \frac{5}{3} \, \text{V} \)
• B. \( \frac{14}{3} \, \text{V} \)
• C. \( \frac{8}{3} \, \text{V} \)
• D. \( \frac{11}{3} \, \text{V} \)

Hint:

In circuits with resistors in series, the voltage across each resistor is proportional to its resistance.

Answer 1

The Correct Option is B

Step 1: Equivalent Resistance.
We need to find the total resistance in the circuit. The 1\(\Omega\) and 2\(\Omega\) resistors are in series, and their equivalent resistance is: \[ R_{\text{eq}} = 1\Omega + 2\Omega = 3\Omega \] Then, the total voltage across the series combination of resistors is \(4V + 2V = 6V\).
Step 2: Voltage Division.
The voltage across the 1\(\Omega\) resistor can be found using the voltage division rule: \[ V_{\text{PQ}} = \frac{1\Omega}{3\Omega} \times 6V = \frac{14}{3} \, \text{V} \] Thus, the voltage across PQ is \( \frac{14}{3} \, \text{V} \).