Question

In the following circuit, the internal resistance of the cell is 5 \( \Omega \), the current drawn from the cell will be:

• A. 0.4 A
• B. 0.1 A
• C. 0.2 A
• D. 0.3 A

Hint:

When calculating the current in a circuit, use Ohm's law and ensure you correctly combine the resistances.

Answer 1

The Correct Option is C

Step 1: Finding the Total Resistance.
The resistances in the circuit are 10 \( \Omega \), 30 \( \Omega \), 50 \( \Omega \), and 90 \( \Omega \). First, combine the resistances as follows: \[ R_1 = 30 \Omega + 50 \Omega = 80 \Omega \] Then, \[ R_2 = 80 \Omega + 90 \Omega = 170 \Omega \] Finally, the total resistance is: \[ R_{\text{total}} = R_1 + R_2 = 170 \Omega + 10 \Omega = 180 \Omega \] Step 2: Applying Ohm's Law.
Now, use Ohm's Law \( V = IR \) to find the current drawn from the cell. The total voltage across the cell is 7V, and the total resistance is 180 \( \Omega \). Thus, the current is: \[ I = \frac{V}{R} = \frac{7V}{35 \Omega} = 0.2A \] Step 3: Final Answer.
Thus, the current drawn from the cell is 0.2 A.