Question

In the following circuit, current through ACB if each resistance $R=4\Omega$ is

• A. 1 A
• B. 2 A
• C. 3 A
• D. 4 A

Hint:

In a symmetric balanced bridge, current splits equally between the top and bottom branches.

Answer 1

The Correct Option is B

Step 1: Analysis
The circuit is a balanced Wheatstone bridge ($R/R = R/R$). No current flows through the central resistor CD.

Step 2: Calculation
- Path ACB has $R+R = 4+4 = 8\Omega$. - Path ADB has $R+R = 4+4 = 8\Omega$. - Equivalent resistance $R_{eq} = 8/2 = 4\Omega$.

Step 3: Analysis
Total current $I = V/R_{eq} = 16/4 = 4$ A.

Step 4: Conclusion
Since the paths are symmetric, the current splits equally. Current through ACB $= 4/2 = 2$ A. Final Answer: (B)