Question:

In the figure shown below reactant A (represented by square) is in equilibrium with product B (represented by circle). The equilibrium constant is :

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For \(\mathrm{A \rightleftharpoons B}\), \(K_c = [B]/[A]\) = (number of circles)/(number of squares), as the volume is common.
Updated On: Nov 5, 2026
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The Correct Option is B

Solution and Explanation

For \(\mathrm{A \rightleftharpoons B}\) in one container, \(K_c = [B]/[A]\), and since the volume is common, \(K_c\) = (number of B particles)/(number of A particles).
From the figure: squares (A) = 6 and circles (B) = 11 to 12, so \(K_c \approx 12/6 = 2\) (nearest option).
Answer: (2) 2
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