Step 1: Set up:
Let AP = 4k and PB = 3k, so AB = 7k. Q lies on BC and D lies on AB.
Step 2: PQ || AC:
In \( \Delta \)ABC, PQ is parallel to AC, so \( \dfrac{BQ}{BC} = \dfrac{BP}{BA} = \dfrac{3k}{7k} = \dfrac{3}{7} \).
Step 3: QD || CP:
In \( \Delta \)BCP, QD is parallel to CP, so \( \dfrac{BD}{BP} = \dfrac{BQ}{BC} = \dfrac{3}{7} \). Hence \( BD = \dfrac{3}{7}\times 3k = \dfrac{9k}{7} \).
Step 4: Find PD:
\( PD = PB - BD = 3k - \dfrac{9k}{7} = \dfrac{12k}{7} \).
Step 5: Ratio:
\( AP : PD = 4k : \dfrac{12k}{7} = 28 : 12 = 7 : 3 \).
Final Answer:
The correct option is (4): 7 : 3